30x^2/5x-4=0

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Solution for 30x^2/5x-4=0 equation: 



30x^2/5x-4=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We multiply all the terms by the denominator


30x^2-4*5x=0

Wy multiply elements

30x^2-20x=0

a = 30; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·30·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*30}=\frac{0}{60}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*30}=\frac{40}{60}
=2/3
$

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